Submissions | Add Your Comments | Physics Site Links | Home Page |
| Email: Miles Mathis |
The Moon Gives Up a
Secret For
this reason I have I studied the Moon’s data quite closely. To my mind our
physical theories have recently traveled too far from home. Theories on
black holes and other exotics, theories of the first seconds in the
universe, theories of strings vibrating below the Planck limit. These may
be interesting, but to me they are not as interesting as objects in our
nearer environs, things we know a bit more intimately. It is from these
things that we are likely to learn the next secrets of the cosmos.
As proof of this rather non-modern
assertion, I will offer in this paper some basic data from the Moon and
show that it contains an astonishing secret that has so far lain unheard.
I don’t know that anyone
has ever considered this. If they had considered that gravity might vary
directly with radius, then this data from the Moon would have been the
first thing to put them off the idea. Data from the rest of the solar
system, and indeed the universe, would be the second thing to put them off
it. The ratios from the Moon are close, but they are far enough apart to
deter all but the most eccentric from following up any idea that they
might be related. If they were related, shouldn’t the gravity of the Moon
be 1/3.67 that of the Earth? It is not and that is all there is to it.
Once we get to the Sun, and then to exotics like black holes and neutron
stars, the idea that gravity is simply a function of radius is ludicrous.
Why even do any math on the Moon to pursue it one way or another?
Without a very strong lead, none but a
fool would pursue the idea. After all, what could possibly cause the
variance in the Moon? What could make up the difference between 1/3.67 and
1/6? Whatever it was would have to make up much greater differences for
the Sun and exotics. Well, it turns out that there is a very strong lead,
and it is called the E/M field. Quantum physicists know that at their
level the E/M field totally swamps the gravitational field, but at the
macro-level the E/M field has been pretty much ignored. As I will show,
the strength of the E/M field of the Earth at its surface is not
sufficient to effect g until the third decimal point, so it is not
surprising that terrestrial scientists would get used to ignoring it. If
they ignore it concerning g, it is not surprising that they would also
ignore it concerning the field of the Moon. They would assume that the
Moon’s field is proportionally weaker than the Earth’s, since the Moon is
known to be almost non-magnetic, as a whole.
This ignoring of the E/M field has been
a grave error, however. An E/M field continues to exist even in the
absence of the expression of its magnetic component, as we now know. Venus
and Mars exclude the Solar Wind just as if they had powerful
magnetospheres, even though they do not. In fact, I will show with a few
very simple postulates and some even simpler math that the E/M field of
the Moon is quite sufficient to make up the difference between 1/3.67 and
1/6. I will go even further and show that the E/M field of the Moon is
exactly sufficient to make up that difference. This will prove that the
total weight-causing fields of both the Earth and the Moon are sums of the
gravitational field and the E/M field, and that the gravitational fields
can be shown to vary exactly as the radius of the object. It is not
necessary for me to finalize a mechanical description of the E/M field at
the quantum level here. All that is necessary is that you accept that
physical objects are affected by a large E/M field by feeling an
exclusionary force. There is nothing revolutionary in this postulate,
since we already accept that meteors are affected not only by the
atmosphere of the Earth, but by its E/M field. The Solar Wind is also
excluded by the E/M field, as I have already stated. Plasma research has
provided lots of new data in this direction, but we have always had data
that showed the basic exclusionary nature of the field.
The second postulate concerns the
variance of an E/M field when it is created by a spherical object. We know
that in a non-spherical E/M field the field varies with the inverse square
law. But since the E/M field is mediated by discrete particles, it must
vary in an additional way when the field is spherical. The field lines
emitted by a sphere will not be even nearly parallel. They will spread out
as the radius increases. This means that the field must become less dense
at greater radii: the distance between photons must increase. Since the
surface area of a sphere is given by 4πr2, the density of the
field will drop off with the inverse square law. But we must add this to
our other inverse square law, since they are unrelated. This means that
the spherical E/M field will vary as
1/r4. Some will say that if
the gravitational field is expressed by the graviton, the same
consideration must apply to it. But this is false. The gravitational field
was always spherical, and the inverse square law always applied to the
spherical field. This has been known empirically for centuries, so that we
do not need to figure a special case for the gravitational field. There is
no rectilinear gravitational field, like the E/M field, where the inverse
square law also applies. Therefore we do not have to add effects.
gE / gM = 3.672 But the current number
for gM is 1.62 m/s2. That seems like a huge amount
of acceleration to make up, and I can understand your doubts. When I first
did the math I thought there was little chance the numbers would work, to
be honest. I was just following an idea. But watch closely: gE - EE = 9.8
m/s2 I have also postulated that the
gravitational part of this acceleration should be proportional to the
radii. gE / gM = 3.672 And I have just postulated
that the E/M field is proportional to 1/r4. But that last equation is
assuming that the Earth and Moon have the same density. So I must now
correct for density. DE /DM = 5.52/3.344 = 1.6507
= 1/.6057 So, we just substitute: .2723
gE - 110.12 EE = 1.62
m/s2 We did not get an exact match in the
third decimal place only because we used 9.8 m/s2 for
gE in the first equation. We must now add .009545 to that, and
if we do we get 2.671 m/s2 in the first equation as
well. This is so astonishing that your
first reaction is to assume that the math is circular. Well, it is. I have
not proved that the E/M field of the Moon has that value or that
gravity depends only on a radius. But I have shown that it is possible to
explain the numbers in this way. If you let the E/M increase faster than
the gravitational field decreases, then you discover a situation that
begins to give us different numbers, and that is capable of describing
gravity in a different way. It may be
that the E/M field varies as 1/r3. It is known that the
magnetic field of a dipole varies in this way, so that the electrical
field may vary in the same way in the situation we are looking at: large
E/M fields created by large macro-bodies. This field variance would also
work with my theory, we would just get different numbers for the actual
fields of the Moon and Earth. I am presently following other problems to
decide which of the two variances my theory must finally
prefer. Notice that the number I have
arrived at for the E/M acceleration at the surface of the Earth is quite
small. This explains why it has always been neglected. Physicists have
correctly assumed that it was negligible in most cases, and they went on
to assume the same for the Moon. Why, they thought, would the Moon have an
E/M field that was more active at the surface of the Moon than the Earth’s
E/M field is at its surface? The idea was counterintuitive, so no one has
ever done any math to show it one way or another. I have just shown, using
postulates that are hardly revolutionary, that the Moon’s E/M field should
be expected to offset its gravitational field quite strongly.
You will say that we have tested the
fields on the Moon already and found them to be quite small. There are two
problems here. One, our tests were designed to measure local fluctuations
in the E/M field, and especially the magnetic component of that field.
This is not the same thing as measuring the strength of the entire field
at a distance. Two, the tests of the E/M field are compromised just like
all our tests of the gravitational field have been. In neither case have
we been successful in separating the effects of the two fields. Whether we
are measuring a gravitational field or an E/M field, we must measure a
force on a body. But the force on the body is a composite of the two. A
differential. If we do not take this into account (and we don't) there is
no way we can know what the strength of each field is alone. We would have
to block one field or the other in our measurements, and we have never
done this. According to my theory, you cannot block the field of gravity,
since it just a real acceleration. You cannot block an acceleration. But
the E/M should be blockable. If it is the radiation of photons, we should
be able to block this radiation. It is unclear how successful this
blocking might be expected to be. If you block off a small area of an E/M
field, it is doubtful that you can thoroughly block the effects of that
field. However, it should be possible to design a simple experiment that
would test my theory. Dropping ball bearings above a large sheet of lead
would be a beginning. It may be that an experiment that direct would yield
an acceleration measurably above 9.8
m/s2. The math above also
implies that all celestial bodies, including exotics like black holes and
white dwarfs, have gravitational fields that vary as their radii vary. It
suggests in the strongest possible way that the huge additional forces
hypothesized for exotics are mainly a function of a super-strong E/M
field, and have nothing to do with gravity per se. This means we
must reconsider all our theories for exotics, and indeed for non-exotics.
Our theory has existed with a very large hole in it and now we must
re-calculate many things. I think it would be an extraordinary coincidence
if the Moon and the Earth had gravitational fields that varied as their
radii and other objects did not. It cannot be because they are of similar
origin, since we know that their densities differ. If density is not a
factor between the Earth and the Moon, then why should it be a factor in
other objects? The only reason we have finally discovered this secret with
the Moon is that its statistics are entirely more settled and complete. We
have been perfecting this data for centuries, and the data finally bears
fruit. Some will say, “What do you mean
density is not a factor? You had to correct for it, it must be a factor!”
Yes, it is a factor in the E/M field. A denser object creates a stronger
E/M field and I had to correct for the fact that the Moon is not as dense
as the Earth. But this correction did not affect the gravitational fields.
That is what the final number shows. I predicted that the gravitational
field was a straight outcome of the radius, with no other factors
involved. That is where we got the first number 2.671 above. That first
equation has no correction for density. It is radius and nothing
else.
Miles Mathis
The Moon is the only celestial
body we have actually visited. We have stepped on its surface, collected
rocks, hit golfballs into its bunkers. The data we have from the Moon is
therefore in some sense privileged. It is not based on assumption or
speculation. It is not based solely on calculation. It is based on
first-hand measurement. We have data collected by hand. Concerning the
Moon, we are now a primary source.
Let us start with three basic measurements of the Moon: it’s vital
stats, if you will. It’s mass is 1/81 that of the Earth. It’s radius is
1/3.67 that of the Earth. And it’s gravity at the surface is about 1/6
that of the Earth. I have given all these numbers relative to the Earth
for a reason. I looked hard at this very limited data and the thought
occurred to me that the gravity ratio and the radius ratio were rather
close. Much closer than the mass ratio, at any rate. Might there be a
direct link?
My proof
relies on only two postulates. The first is that the E/M field is an
exclusionary field created by bombardment or an equivalent mechanism. This
postulate is orthodox, since most physicists accept that the field must be
mediated by particles, probably photons of some sort. Some quantum
physicists now prefer the concept of the messenger photon, a photon that
is capable of giving different messages to negative charges and positive
charges; but a simpler mechanical explanation is that the field is a
straight bombardment of photons, either as a sort of fluid or as a sort of
hail of tiny bullets.
Given these two postulates we can proceed directly to the math.
Let us first make a prediction, using the postulates above. I am claiming
that that I can show that the gravitational fields of the Moon and the
Earth are directly proportional to their radii. Let us do the math to show
what the Moon’s gravitational field would have to be if that were
true.
9.8 m/s2 /
gM = 3.672
gM = 2.669
m/s2
We
know that the total field of the Earth at its surface creates an
acceleration of 9.8 m/s2 and we hypothesize that this is the
gravitational field minus the E/M field [the gravitational field is an
attractive field and the E/M field is a repulsive field]. And we know the
same for the Moon.
gM - EM = 1.62 m/s2
gM = .2723
gE
EE
/EM = 1/3.6724 = .0055
EM = 181.81
EE
EM = 110.12 EE
gE - EE = 9.8
m/s2
.2723gE - .2723EE = 2.6685
m/s2 [subtract the two
equations]
-109.85EE = -1.0485 m/s2
EE = .009545 m/s2
EM = 1.051
m/s2
gM - EM = 1.62
m/s2
gM = 2.671 m/s2
You can see that the math bore out my prediction exactly. Once
we correct for the presence of the E/M field, the Earth and the Moon have
gravitational fields that are exactly proportional to their radii.
If this postulate is true, the implications of this are
beyond number. I could not begin to address them here, even as a list. I
begin to address them in other papers, but it will take physics decades to
come to terms with the full import of this discovery. Those who have
claimed that physics is nearly over will be glad to discover that they
have something left to do.